Comments on: Fixing An "Unterminated String Literal" Error In An AJAX JavaScript HttpRequest https://www.dougv.com/2008/06/10/fixing-an-unterminated-string-literal-error-in-an-ajax-javascript-httprequest/ ASP.NET, PHP, XML, JavaScript, Web geekery, Entrepreneurship Fri, 18 May 2012 10:23:05 +0000 hourly 1 http://wordpress.org/?v=3.3.2 By: Doug Vanderweide https://www.dougv.com/2008/06/10/fixing-an-unterminated-string-literal-error-in-an-ajax-javascript-httprequest/#comment-1022 Doug Vanderweide Wed, 09 May 2012 12:36:22 +0000 http://www.dougv.com/blog/?p=342#comment-1022 Without seeing the specific code, I can't help you, Darren. See the "<a href="https://www.dougv.com/need-more-help/" rel="nofollow">Need more help or want to say thanks</a>" link on the upper-right-hand corner for more information. Without seeing the specific code, I can’t help you, Darren. See the “Need more help or want to say thanks” link on the upper-right-hand corner for more information.

]]> By: Darren https://www.dougv.com/2008/06/10/fixing-an-unterminated-string-literal-error-in-an-ajax-javascript-httprequest/#comment-1021 Darren Wed, 09 May 2012 12:33:18 +0000 http://www.dougv.com/blog/?p=342#comment-1021 Hi Doug, Thanks for this article! I'm getting the 'Unterminated string literal' error message when trying to view the records of a particular client. I think I need to add the 'addslashes' to 'site_name' somehow but as I'm a newbie to php I'm not sure exactly how to do it. Could you take a look at the code and advise me please? The error message is flagging up this piece of code: $myarray=array(); -------------------------------------------- Thanks! Hi Doug,
Thanks for this article! I’m getting the ‘Unterminated string literal’ error message when trying to view the records of a particular client. I think I need to add the ‘addslashes’ to ‘site_name’ somehow but as I’m a newbie to php I’m not sure exactly how to do it. Could you take a look at the code and advise me please?

The error message is flagging up this piece of code: $myarray=array();
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Thanks!

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